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Sep 11 2012, 05:37 PM
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#1
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Joined: 11-September 12 Posts: 9 |
Sorry, I'm new to all this and have 2 questions. First, I checked everywhere but only got more confused aboud the analog inputs.
There are single ended and differential inputs, they both say +/-10 volts. I understand that on a differential input one side would go down to -10 volts and the other side to +10 volts (20v range?), but on a single ended one I don't understand this, I thought single ended meant 0-10 volts for example? If I have a 0 to +10 volt signal connected to a single ended input (+ and gnd) do I get the full range of the input? 0v is 0 counts and 10v is 65,536 counts? Also, this is more of an application question, if I need a reference 10v signal could I use a DC-DC converter on an analog output and monitor this signal with an analog input so it could be self calibrating? It would only use a few mA. Thanks! |
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Sep 12 2012, 07:38 AM
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#2
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Joined: 9-June 03 Posts: 7527 |
You are confusing differential & single-ended with bipolar & unipolar. See the "Differential Analog Inputs" app note:
http://labjack.com/support/app-notes/diffe...l-analog-inputs The U6 has 4 input ranges: +/-10V, +/-1V, +/-0.1V, or +/-0.01V. These are the same whether differential or single-ended, and mean that the difference between the positive channel and negative channel must be in that range. For a differential input the negative channel is another analog input, while for a single-ended input the negative channel is ground. http://labjack.com/support/u6/users-guide/2.6 You can see that the actual nominal input range at +/-10V is -10.6V to +10.1V: http://labjack.com/support/u6/users-guide/2.6.2 Appendix A has more specifications about the analog inputs, and note 7 points you to the signal range tables in Section 2.6.5: http://labjack.com/support/u6/users-guide/appendix-a http://labjack.com/support/u6/users-guide/2.6.5 The easiest way for you to get 10V at <=3mA would probably be the LJTick-DAC: http://labjack.com/support/ljtick-dac/datasheet Besides the LJTDAC, likely solutions would involve 2 parts: -First, you would need a power-supply of perhaps +12V. You could use a DC-DC converter to convert 5V to 12V such as the 445-2448 from Digikey, or you could just use a wall-wart with 12V output. -Then, you have something to provide a regulated 10V output from the 12V power-supply. One option would be to search Digikey for a "voltage reference" that would do the job (perhaps the AD581KH). Another option would be to put an LT1490A op-amp on an analog output (see Section 2.7.1.2). |
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Sep 12 2012, 09:28 AM
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#3
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Joined: 11-September 12 Posts: 9 |
Yes, I was thinking as if they where bipolar!
Think I got it now, I can connect my 0-10v signal single-ended and would cover the whole range of the input. I could have a signal of 1-11v in a differential setting (As long as I do not exceed 11.9v) and it would give me the same "counts" or raw output as the above configuration. Right? And the LJTick-DAC does seems like the easiest way to solve the reference voltage. Thank you! |
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Sep 12 2012, 02:52 PM
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#4
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Joined: 9-June 03 Posts: 7527 |
QUOTE Yes, I was thinking as if they where bipolar! Just to be clear, they are always bipolar, whether differential or single-ended. I think you were originally thinking that differential reading are bipolar and single-ended readings are unipolar. QUOTE Think I got it now, I can connect my 0-10v signal single-ended and would cover the whole range of the input. I could have a signal of 1-11v in a differential setting (As long as I do not exceed 11.9v) and it would give me the same "counts" or raw output as the above configuration. I think what you are suggesting here is that if you do a differential reading of AIN0-AIN1, where AIN0 is 11V compared to ground and AIN1 is 1V compared to ground, the differential reading will be 10V. That is correct, but there a few things to consider:
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Sep 14 2012, 02:32 AM
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#5
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Joined: 22-January 09 Posts: 28 |
QUOTE Yes, I was thinking as if they where bipolar! Just to be clear, they are always bipolar, whether differential or single-ended. I think you were originally thinking that differential reading are bipolar and single-ended readings are unipolar. QUOTE Think I got it now, I can connect my 0-10v signal single-ended and would cover the whole range of the input. I could have a signal of 1-11v in a differential setting (As long as I do not exceed 11.9v) and it would give me the same "counts" or raw output as the above configuration. I think what you are suggesting here is that if you do a differential reading of AIN0-AIN1, where AIN0 is 11V compared to ground and AIN1 is 1V compared to ground, the differential reading will be 10V. That is correct, but there a few things to consider:
Look at TI's REF102. I have been using it as "current source" thru 12K ohm series resistor and 1200 ohm reference for measuring a PT1000 probe's resistance. I power it with U6's 12V terminal.
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Sep 14 2012, 07:32 AM
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#6
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Joined: 9-June 03 Posts: 7527 |
I believe eka is suggesting you use Vm+ to get the higher voltage power supply. That is a useful source, but you can't draw much current:
http://labjack.com/support/u6/users-guide/2.11 http://labjack.com/support/u6/users-guide/appendix-a |
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Sep 14 2012, 07:27 PM
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#7
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Joined: 11-September 12 Posts: 9 |
I was looking for at least 5 mA to be on the safe side, so VM+ is not an option. Iīm testing a variable DC-DC booster thatīs supposed to regulate within 1%, will see how it turns out.
Meanwhile I have a load of software issues to resolve :) Thank you both for your replies! |
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Oct 3 2012, 04:04 AM
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#8
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Joined: 22-January 09 Posts: 28 |
Sorry about not indicating Vm+ as source of 12V for Ref102.
Ref102 is rated for 10ma, so wall-wart driving it would work. |
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